Question

The autosomal (not X-linked) gene for brachydactyly, short fingers, is dominant to normal finger length. Assume that a female with brachydactyly in the heterozygous condition is married to a man with normal fingers. What is the probability that
a) their first child will have brachydactyly?
b) their first two children will have brachydactyly?
c) their first child will be a brachydactylous girl?

Answer

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