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Question
Table 7.4
| Activity | Predecessor | Time(weeks) |
| A | -- | 8 |
| B | A | 6 |
| C | -- | 4 |
| D | C | 9 |
| E | A | 11 |
| F | B | 3 |
| G | D, E, F | 1 |
Using Table 7.4, what is the minimum number of activities that would have to be crashed to cause a decrease in the project's earliest completion date?
A) one activity
B) two activities
C) three activities
D) four or more activities
Answer
This answer is hidden. It contains 58 characters.
Related questions
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Q:
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Construct a 3-sigma and R-chart for the length in centimeters of a part from the following table. Sample #
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Q:
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Q:
Consider this list of jobs that have just arrived and are ready for processing. They all require processing first on machine 1 and then on machine 2. Both machines are now idle. Develop a schedule that minimizes makespan and calculate this makespan time. Now assume that each job can be split into two jobs, each having half the duration on both machine 1 and machine 2. Using the original sequence that minimized average flow time, calculate the flow times for all split jobs What is the effect of this new schedule on the average flow time for these split jobs? Job
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14
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11
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12
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22
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13
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10
12 8
8
13