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Question
Final tableaus cannot be used to conduct sensitivity analysis.Answer
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Related questions
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Q:
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Q:
Use the following table and the information to answer the questions below.
In the following transportation matrix, all cells except 2C have been evaluated and show no improvement. Evaluate that cell. What is the reduced cost if we decide to allocate to cell 2C?
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Q:
The transportation method is a linear programming technique where linearity can be found in which of the following ways?
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B) The total cost associated with a given plan is a linear function of shipping costs.
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If we are solving a 0-1 integer programming problem, the constraint x1 + x2 = 1 is a mutually exclusive constraint.
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The divisibility assumption is violated by integer programming.
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In a total integer model, all decision variables have integer solution values.
Q:
The landlord ran the model in Excel and received the sensitivity report for the constraints as contained in the table. Which of the following statements is correct?FinalShadowConstraintAllowableAllowableCellNameValuePriceR.H. SideIncreaseDecrease$B$12Total Time Weeks4.0013.6441.13.1E-16$E$10Total Cost3000.000.0130005503.1E-13$I$4wood floors Included?1.0067.2711.27E-164.6E-01$I$5kitchen tile Included?1.0025.4517.63E-172.8E-01$I$6back door Included?0.000.0011.00E+301.0E+00$I$7garage door opener Included?1.0011.8215.09E-161.0E+00A) If there are 2 more weeks available for work, it would be possible to increase rent by $27.28 per weekB) Given the scenario, it is evident that a constraint is missing.C) If the landlord installed two garage doors, rent could be increased by $23.64.D) Given the scenario, it is evident that the objective function is misstated.
Q:
The landlord uses the following scheme for decision variables:x1 = contractor works on wood floorsx2 = landlord works on wood floorsx3 = contractor works on kitchen tilex4 = contractor works on kitchen tilex5 = contractor works on back doorx6 = contractor works on back doorx7 = contractor works on garage doorx8 = contractor works on garage doorWhich of these constraints would not be appropriate for this scenario?A) 2700x1 + 400x2 + 2500x3 + 1000x4 + 600x5 + 250x6 + 350x7 + 400x8≤ 3000B) 1x1 + 2x2 + 1.5x3 + 3x4 + 5x5 + 1x6 + 0.25x7 + 0.5x8≤ 4C) x3 + x4 = 1D) x1, x2, x3, x4, x5, x6 , x7, x8≥0 and integer
Q:
The landlord uses the following scheme for decision variables:x1 = contractor works on wood floorsx2 = landlord works on wood floorsx3 = contractor works on kitchen tilex4 = contractor works on kitchen tilex5 = contractor works on back doorx6 = contractor works on back doorx7 = contractor works on garage doorx8 = contractor works on garage doorWhat should the objective function be?A) Min Z = 2700x1 + 400x2 + 2500x3 + 1000x4 + 600x5 + 250x6 + 350x7 + 400x8B) Min Z = 2700x1 - 400x2 + 2500x3 - 1000x4 + 600x5 - 250x6 + 350x7 - 400x8C) Max Z = 100x1 + 100x2 + 80x3 + 80x4 + 15x5 + 15x6 + 20x7 + 20x8D) Max Z = 100x1 - 100x2 + 80x3 - 80x4 + 15x5 - 15x6 + 20x7 - 20x8