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Question
At the initial basic feasible solution at the origin, only slack variables have a value greater than:A) 0
B) 1
C) -1
D) 1 or -1
Answer
This answer is hidden. It contains 1 characters.
Related questions
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The landlord ran the model in Excel and received the sensitivity report for the constraints as contained in the table. Which of the following statements is correct?FinalShadowConstraintAllowableAllowableCellNameValuePriceR.H. SideIncreaseDecrease$B$12Total Time Weeks4.0013.6441.13.1E-16$E$10Total Cost3000.000.0130005503.1E-13$I$4wood floors Included?1.0067.2711.27E-164.6E-01$I$5kitchen tile Included?1.0025.4517.63E-172.8E-01$I$6back door Included?0.000.0011.00E+301.0E+00$I$7garage door opener Included?1.0011.8215.09E-161.0E+00A) If there are 2 more weeks available for work, it would be possible to increase rent by $27.28 per weekB) Given the scenario, it is evident that a constraint is missing.C) If the landlord installed two garage doors, rent could be increased by $23.64.D) Given the scenario, it is evident that the objective function is misstated.
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The landlord uses the following scheme for decision variables:x1 = contractor works on wood floorsx2 = landlord works on wood floorsx3 = contractor works on kitchen tilex4 = contractor works on kitchen tilex5 = contractor works on back doorx6 = contractor works on back doorx7 = contractor works on garage doorx8 = contractor works on garage doorWhich of these constraints would not be appropriate for this scenario?A) 2700x1 + 400x2 + 2500x3 + 1000x4 + 600x5 + 250x6 + 350x7 + 400x8≤ 3000B) 1x1 + 2x2 + 1.5x3 + 3x4 + 5x5 + 1x6 + 0.25x7 + 0.5x8≤ 4C) x3 + x4 = 1D) x1, x2, x3, x4, x5, x6 , x7, x8≥0 and integer
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The landlord uses the following scheme for decision variables:x1 = contractor works on wood floorsx2 = landlord works on wood floorsx3 = contractor works on kitchen tilex4 = contractor works on kitchen tilex5 = contractor works on back doorx6 = contractor works on back doorx7 = contractor works on garage doorx8 = contractor works on garage doorWhat should the objective function be?A) Min Z = 2700x1 + 400x2 + 2500x3 + 1000x4 + 600x5 + 250x6 + 350x7 + 400x8B) Min Z = 2700x1 - 400x2 + 2500x3 - 1000x4 + 600x5 - 250x6 + 350x7 - 400x8C) Max Z = 100x1 + 100x2 + 80x3 + 80x4 + 15x5 + 15x6 + 20x7 + 20x8D) Max Z = 100x1 - 100x2 + 80x3 - 80x4 + 15x5 - 15x6 + 20x7 - 20x8